Respuesta :
Answer:
1.6727 meters
Explanation:
The inicial kinetic energy of the mass can be calculated using the formula:
E = mv^2/2
where m is the mass and v is the speed, so:
E = m*1.9^2/2 = 1.805m
All this energy is lost to the friction between the mass and the ground.
The friction force is F = m*g*u, where g is gravity and u is the coefficient of kinetic friction.
The energy that this force will generate is:
E = F * d, where d is the distance.
So, making the inicial kinetic energy equal to the energy dissipated by the friction, we have:
1.805m = m*g*u*d
9.81*0.11*d = 1.805
d = 1.805/(9.81*0.11) = 1.6727 meters
Answer:
Distance = 1.674m
Explanation:
By the work energy theorem:-
W = ΔKE
W is work while KE is kinetic energy
Now we know that w has a formula;
W = Force x Distance and KE = (1/2)mv²
Thus,
F(friction) x s = (1/2)mv²
Now frictional force is = μmg
Where,
μ is coefficient of kinetic friction
Thus,
μmg•s = (1/2)mv²
m will cancel out to give;
μg•s = (1/2)v²
Let's make s the subject;
s = v²/(2gμ)
From the question,
velocity; v = 1.9 m/s
μ = 0.11 while g is constant at 9.8 m/s²
Thus;
s = (1.9)²/[2 x 9.8 x 0.11]
s = 3.61/2.156
s = 1.674m
