Answer:
A. 5.5 s
B. 0.182 Hz
C. 1.82 m
D. 0.742 m
E. 0.33 m/s
Explanation:
A
Period is the time taken for a complete wave to pass and since for this case we have 6 waves taking 32.8 s then the period will be equivalent to [tex]T=\frac {32.8}{6}=5.466666667s\approx 5.5s[/tex]
Therefore, the period of the waves is approximately 5.5 seconds
B
Normally, frequency of a wave is equivalent to the reciprocal of its period, expressed as
[tex]f=\frac {1}{T}[/tex]
where f is the frequency and T is the period in seconds. Since we already have period in part A above then substituting 5.5 s for T we obtain that
[tex]f=\frac {1}{5.5}=0.181818182 Hz\approx 0.182 Hz[/tex]
C
Wavelength is defined as the horizontal distance between two successive crests or troughs of a wave. The crests are the highest points of a wave and the troughs are the lowest points. Since we are given the distance between two crests already, we assume they are successive then the wavelength is equal to 1.82 m
D
Amplitude is the vertical distance between crest and trough to imply the distance between the highest and lowest point of a wave. In this case, that distance is provided as 0.742 m hence that is the amplitude
E
Velocity of a wave is given as the product of wavelength and frequency and expressed as v=fw where v is the velocity, f is the frequency and w is the wavelength. Since we are provided with frequency in part B as 0.182 Hz and the wavelength in part c as 1.82 m then the velocity will be v=0.182*1.82=0.33124 m/s and rounded off as 0.33 m/s
