A fair coin is tossed three times in a succession the sample space is shown where h represents a head and t represents a tail find the probability of getting exactly one tail

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Answer:

The correct answer is [tex]\frac{3}{8}[/tex]

Step-by-step explanation:

A fair coin is tossed three times in a succession the sample space is shown where h represents a head and t represents a tail.

Let the experiment A denote that we get exactly one tail in three successive toss of a coin.

Sample space = { hhh, hht, hth, thh, tth, tht, htt, ttt} = 8

Favorable sample = { hht, hth, thh } = 3

Probability of the A = [tex]\frac{Favorable}{Total}[/tex] = [tex]\frac{3}{8}[/tex] = 0.375.

Thus the probability of getting exactly one tail in three successive toss of a fair coin is given by 0.375

The probability of having exactly one head after tossing the coin three times is 3/8.

Data;

  • head = h
  • tail = t

The probability of exactly one tail

The probability of getting exactly one tail can be found from the sample space.

Sample space = { hhh, hht, hth, thh, tth, tht, htt, ttt} = 8

The number of exactly one tail here is 3

The probability of exactly one tail is

[tex]P = \frac{3}{8}[/tex]

The probability of having exactly one head after tossing the coin three times is 3/8.

Learn more on probability here;

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