kkwynn1999
kkwynn1999 kkwynn1999
  • 27-02-2017
  • Mathematics
contestada

can anyone help me out

can anyone help me out class=

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morgeron
morgeron morgeron
  • 27-02-2017
maximum profit due to the feasibility graph....we take where the two lines cross...(6,5). These figures are substituted into the equation and the result is the max profit...

p = 3x + 2y
p = 3(6) + 2(5)
p = 18 + 10
p = 28
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