A building 210 feet tall casts a 50 foot long shadow. If a person looks down from the top of the​ building, what is the measure of the angle between the end of the shadow and the vertical side of the building​ (to the nearest​ degree)? (Assume the​ person's eyes are level with the top of the​ building.)

Respuesta :

Answer:

to the nearest degree = 77°

Explanation:

This is a question under trigonometry

from the question we can find that The building is 210 feet tall and the length of its shadow is 50 feet.

The relationship between opposite and adjacent of the triangle is tan

Therefore tanθ = [tex]\frac{50}{210}[/tex]

θ = tan⁻¹ 0.2380

= 13.39°

then we have to calculate the measure of the angle between the end of the shadow and the vertical side of the building​ , which is equal to

90 - 13.39=

=76.61°

to the nearest degree = 77°

The angle between the shadow's end and vertical side of the building would be [tex]= 76.6[/tex]°

Given that,

Height of the building [tex]= 210 ft.[/tex]

Length of the shadow [tex]= 50 foot[/tex]

To find,

The angle between the shadow's end and vertical side of the building = ?

So,

θ = [tex]tan^{-1}[/tex] [tex]210/50[/tex]

θ [tex]= 76.6[/tex]°

Thus, the angle between the shadow's end and vertical side of the building would be [tex]= 76.6[/tex]°

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