For this case we have the following expression:
[tex] \frac{x^2+x-6}{x^2-2x-15} [/tex]
Factoring the numerator we have:
[tex] \frac{(x+3)(x-2)}{x^2-2x-15} [/tex]
Factoring the denominator we have:
[tex] \frac{(x+3)(x-2)}{(x-5)(x+3)} [/tex]
Canceling similar terms we have:
[tex] \frac{(x-2)}{(x-5)} [/tex]
Answer:
the folowing is equal to the rational expression when x is not equal to 5 or -3:
[tex] \frac{(x-2)}{(x-5)} [/tex]
Note: it seems that the answer is not between the options given. Please check the options again and verify that they are well written.