Answer: a=4, b=-8, c=-3
Step-by-step explanation: This equation isn't in standard form. To get it there, subtract -3 from both sides. This gets you an equation of 4x^2-8x-3.
The standard form is ax^2+bx+c.
A is the number before x^2 (4). B is the number before x, and since it's subtracted it's negative (-8). C is the last number, and since it's subtracted it's negative (-3).
