Question

What is the volume of 0.366 moles of helium collected at 25 C and a
pressure of 0.98 atm?*

Answer 1

Answer:

V = 9.14 L

Explanation:

Given data:

Volume of helium = ?

Number of moles = 0.366 mol

Temperature = 25°C (25+273 = 298 K)

Pressure of gas = 0.98 atm

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

V = nRT/P

V = 0.366 mol ×  0.0821 atm.L/ mol.K  × 298 K / 0.98 atm

V = 8.95 L / 0.98

V = 9.14 L