Answer : The area of the 12 equal long pieces is, [tex]\frac{455}{6144}in^2[/tex]
Step-by-step explanation :
As we are given that:
Width of rectangle = [tex]1\frac{5}{8}in=\frac{13}{8}in[/tex]
Length of rectangle = [tex]8\frac{3}{4}in=\frac{35}{4}in[/tex]
When student cuts of 3/4 from width and 3/4 from height then the new width and length of rectangle will be:
New width = [tex]\frac{13}{8}-(\frac{13}{8}\times \frac{3}{4})=\frac{13}{8}\times \frac{1}{4}=\frac{13}{32}in[/tex]
New length = [tex]\frac{35}{4}-(\frac{35}{4}\times \frac{3}{4})=\frac{35}{4}\times \frac{1}{4}=\frac{35}{16}in[/tex]
Now student cuts in 12 equal long pieces.
New length = [tex]\frac{\frac{35}{16}in}{12}=\frac{35}{192}in[/tex]
New width = [tex]\frac{13}{32}in[/tex]
Now we have to calculate the area of the 12 equal long pieces.
Area of rectangle = Length × Width
Area of rectangle = [tex]\frac{35}{192}in\times \frac{13}{32}in[/tex]
Area of rectangle = [tex]\frac{455}{6144}in^2[/tex]
Therefore, the area of the 12 equal long pieces is, [tex]\frac{455}{6144}in^2[/tex]
