Question

a bowling boal has a mass of 5 kg. what happens to its momentum when its speed increase from 1 m/s to 2 m/s?

Answer 1

Answer:

change in momentum (p) = m. (v₂ -v1)

                                          = 5. (2-1)

                     momentum = 5 m/s.

Answer 2

Answer:

Momentum also increases (doubles from 5 kgm/s to 10 kgm/s)

Explanation:

the momentum is given by

$p=mv$

where $p$ is momentum, $m$ is mass of thebowling ball ($m=5kg$), and $v$ is speed.

The momentum when $v=1m/s$ is:

$p=(5kg)(1m/s)\\p=5kgm/s$

and the momentum when $v=2m/s$ is:

$p=(5kg)(2m/s)\\p=10kgm/s$

so we can see that the momentum doubles from 5 kgm/s to 10 kgm/s.