The solution is 4 and -4.
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax^2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term. The first condition for an equation to be a quadratic equation is the coefficient of x2 is a non-zero term(a ≠ 0).
The roots of a quadratic equation are the two values of x, which are obtained by solving the quadratic equation. These roots of the quadratic equation are also called the zeros of the equation. For example, the roots of the equation x2 - 3x - 4 = 0 are x = -1 and x = 4 because each of them satisfy the equation. i.e.,
Given:
4x^2 − 32x + 64 = 0
4( x² - 8x + 16)=0
x² - 8x + 16= 0
x² - 4x - 4x + 16 =0
x(x-4) -4 (x- 4)= 0
1(x-4)(x-4) =0
Hence, the solution is 4, 4.
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