Question

Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, what is the greatest number of rides Daniel can go on? A. Write an inequality that represents Daniel's situation. B. How many rides can Daniel go on?. Justify your answer.

Answer 1

Answer:

1.5*(Max. no. of rides) + 4 = 25

$No. of rides\leq 14$

Max. No. of rides = 14

Step-by-step explanation:

The equation can be written as:

(Max. No. of Rides)(Cost of each ride) + Admission Cost = Total Money at Hand

Let,

'R' be the maximum no. of rides Daniel can go on.

Cost of each ride=$1.5

Admission Cost=$4

Total Money at Hand=$25

Substituting values in above equation we get,

$R*1.5+4=25\\R*1.5=25-4\\R*1.5=21\\R=\frac{21}{1.5}\\R=14$

Hence, the max. no. of rides Daniel can take is 14.

The inequality equation can be written as:

$No. of rides\leq 14$