Question

Which is the next logical step in balancing the given equation?
CS2(l) + Cl2(g) CCl4(l) + S2Cl2(l)
A.) Place the coefficient 2 in front of sulfur dichloride (S2Cl2).
B.)Place the coefficient 3 in front of the chlorine molecule.
C.)Leave the equation alone as it is already balanced.
D.) Place the coefficient 4 in front of carbon disulfide(CS2).
E.)Place the coefficient 2 in front of carbon tetrachloride(CCl4).

Answer 1

B. For balancing this equation: it originally starts with one carbon and two sulfurs and on the reactant side, you still end up with one carbon and two sulfurs. As for chlorine, to balance the equation you will need 6 chlorine molecules, and since chlorine is a diatomic molecule on the left it is Cl2. Therefore, to get 6 molecules of chlorine you will need 3 Cl2.

Answer 2

  CS2(l)  +Cl2(g)→CCl4(l)   + S2Cl2 (l)

The next  logical  step  in balancing  the  equation above is  place  the  coefficient  3  in front  of the chlorine  molecule  ( answer B)

  Explanation

When   coefficient 3  in placed in front  of   chlorine  molecule  the balanced equation is as below

• CS2 (l)  +3Cl2 (g) → CCl4 (l)  + S2Cl2 (l)

• According to the law  of mass  conservation  the  number of atom in side of reactant  should  be equal to the side of product.

• The  reaction above is balanced  because  the number of atom  is equal in both side.

• For example  there  are 2 atoms of S in  side  of product  and 2 atoms of S in the product side.s