Answer:60 rev/min
Explanation:
Given
angular speed of first shaft [tex]\omega _1=420\ rev/min[/tex]
Moment of inertia of second shaft is seven times times the rotational speed of the first i.e. If I is the moment of inertia of first wheel so moment of inertia of second is 7 I
As there is no external torque therefore angular momentum is conserved
[tex]L_1=L_2[/tex]
[tex]I_1\omega _1=I_2\omega _2[/tex]
[tex]I\times (420)=7 I\times (\omega _2)[/tex]
[tex]\omega _2=\frac{420}{7}[/tex]
[tex]\omega _2=60\ rev/min[/tex]