Respuesta :
Answer:
D. None of the above
Step-by-step explanation:
Given the polynomials
P(x)=x³-6x²+6x-23
P(x) can be rewritten as
P(x)=(x²+6)(x−6)+13.
Since, after P(x) was rewritten in
P(x)=(x²+6)(x−6)+13.
So it has a remainder of 13 showing that both (x²+6) and (x-6) is not a factor of the given polynomials.
Also 13 is a constant and not a variable. 13 cannot be factor out of the expression and so it is not even a common factor.
The answer is D, which is none of the above.