Answer:
The molecular formula of the compound is [tex]C_{8}H_{16}O_{4}[/tex]. The molecular formula is obtained by the following expression shown below
[tex]\textrm{Molecular formula }= n\times \textrm{Empirical formula}[/tex]
Explanation:
Given molecular mass of the compound is 176 g/mol
Given empirical formula is [tex]C_{2}H_{4}O[/tex]
Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.
Empirical formula mass of the compound = [tex]\left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}[/tex]
[tex]n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4[/tex]
[tex]\textrm{Molecular formula }= n\times \textrm{Empirical formula}[/tex]
Molecular formula = 4 [tex]\times[/tex] [tex]C_{2}H_{4}O[/tex]
Molecular formula is [tex]C_{8}H_{16}O_{4}[/tex]