Question

The balanced chemical equation for the combustion of hexane is:2C6H14(g) + 19O2(g) The balanced chemical equation for the combustion 12CO2(g) + 14H2O(g)Answer the question in Part 1 through Part 3, if the rate of reaction of C6H14 is 1.43 mol L-1s-1. The rate of reaction of C6H14 is the rate of disappeareance of C6H14.1. What was the rate of formation of CO2?2. What was the rate of formation of H2O?3. What is the rate of reaction of O2?

Answer 1

Answer:

The rate of formation of CO2 = 1.43 mol L-1s-1.

The rate of formation of H2O = 1.43 mol L-1s-1.

The rate of reaction of O2 = 1.43 mol L-1s-1.

Explanation:

2C6H14(g) + 19O2(g) -------> 12CO2(g) + 14H2O(g)

The rate of reaction of C6H14 is 1.43 mol L-1s-1.

The rate of reaction is theoretically defined as the speed of a chemical reaction. It is how fast or how slow the reactants are being used up or products are being formed.

It is the rate of change of concentration, amount etc., of any of the reactant or any of the product with time. The rate of reaction is the same and uniform for any of the products and reactants.

For a chemical reaction, A + 2B -----> 2C

r = -(dA/dt) = -(dB/dt) = (dC/dt)

Hence, the rate of reaction = rate of disappearance of C6H14 = rate of formation of CO2 = rate of formation of H2O = rate of reaction of O2 = 1.43 mol L-1s-1.

Hope this Helps!!!