Respuesta :
Answer: The mass of butane reacting with oxygen gas is 9.76 grams.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For oxygen
Given mass of oxygen gas = 35.1 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen gas}=\frac{35.1g}{32g/mol}=1.096mol[/tex]
For the given chemical reaction:
[tex]2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O[/tex]
By stoichiometry of the reaction:
13 moles of oxygen gas is reacting with 2 moles of butane.
So, 1.096 moles of oxygen gas will react with = [tex]\frac{2}{13}\times 1.096=0.168moles[/tex] of butane.
Now, calculating the mass of butane from equation 1, we get:
Molar mass of butane = 58.12 g/mol
Moles of butane = 0.168 moles
Putting values in equation 1, we get:
[tex]0.168mol=\frac{\text{Mass of butane}}{58.12g/mol}\\\\\text{Mass of butane}=9.76g[/tex]
Hence, the mass of butane reacting with oxygen gas is 9.76 grams.
