Question

What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y-4= (x – 6) and passes through the point (-2,-2)?
y=x-10
y= x + 10
y=x-1
0
0
O y=
x+1
NEED HELP ASAP

Answer 1

Answer:

y = -x - 4

Step-by-step explanation:

First find the slope

y - 4 = (x - 6)

y - 4 = x - 6

y = x - 6 + 4

y = x - 2 (y = mx + C)

Slope m = 1

It is said that the line is perpendicular to a point ( -2, -2)

If two lines are perpendicular, their slope will be negative reciprocal

The negative reciprocal of slope = 1 is -1

Using a slope intercept form as requested by the question

y = mx + C

Inserting the values given

(-2, -2)

We are using point slope form

y - y_1 = m ( x - x_1)

x_1 = -2

y_1 = -2

m = -1

Insert the values

y - ( -2)) = -1( x - (-2))

y + 2 = -1 ( x + 2)---- point slope form

But we are requested to give the answer in slope intercept form

y = mx + C

We have to open the bracket

y + 2 = -1(x + 2)

y + 2 = -x - 2

y = -x - 2 - 2

y = -x - 4 ( slope - intercept form)