Question

What is the quadratic equation with the given roots 3 and -2/3

Answer 1

Answer:

x^2 - 7/3x-2

Step-by-step explanation:

x1=3, x2 =-2/3

(x-x1)(x-x2)=(x-3)(x-(-2/3))=

(x-3)(x+2/3)=x*x+x*2/3-3*x-3*2/3=

x^2 +2/3x-3x-6/3=

x^2 +2/3x-9/3x-2=

x^2 - 7/3x-2