Question

In May, Bradley bought 48 styrofoam balls and decorated them as toy figurines. In June, he sold 19 figurines. In May, Lupe bought 44 styrofoam balls to decorate, and in June, she sold 21 figurines. Make a matrix that represents all of their May purchases and their June sales? .

Answer 1

Step-by-step explanation:

Since we have given that

Number of styrofoam balls bought in May = 48

Number of toy figurines sold in May = 19

Number of styrofoam balls bought in June = 44

Number  of toy figurines sold in June = 21

So, we need to make a matrix that represents all of their May purchases and their June sales :

So, it is given by

                        May                    June

                     Purchases             Sales     

 Bradley      48                            19

 Lupe           49                           21

Hence, the proper matrix will be

$\begin{bmatrix}48 &19 \\ 49&22 \end{bmatrix}$

Answer 2

Answer:

Step-by-step explanation:

Since we have given that

Number of styrofoam balls bought by Bradley in May = 48

Number of toy figurines sold in May = 19

Number of styrofoam balls bought by Lupe in June = 44

Number  of toy figurines sold in June = 21

So, we need to make a matrix that represents all of their May purchases and their June sales :

So, it is given by

                       May                    June

                    Purchases             Sales     

 Bradley       48                            19

 Lupe            49                           21

Thus, we can define a 2x2 matrix in which row 1 represents Bradley and row 2 represents Lupe. The columns then represent May and June. To distinguish between purchase and sale, we will show sale by a positive number and sale with negative; therefore the final matrix will be

$\left[\begin{array}{ccc}48-19\\44-21\end{array}\right]$