Answer:
[tex]f=17\\p=9\\[/tex]
Step-by-step explanation:
Let
[tex]f= Full-time\\p=Part-time[/tex]
Full time rates-$275, Part-time rates-$140
The problem can be expressed as:
[tex]f+p=26...eqtn1\\275f+140p=5935....eqtn2\\[/tex]
Express eqtn1 in terms of f,[tex]f=26-p[/tex]
Substitute f value in eqtn 2.
[tex]=>275(26-p)+140p=5935\\7150-275p+140p=5935\\1215=135p\\p=9\\f=26-9=17\\[/tex]
Therefore, jeds has 17 fulltime and 9 parttime employees.