Answer: 1.25
Explanation:
The ratio of the amplitude of the sound can be calculated using the wave intensity by squaring the amplitude of the two wave particles.
Let the sound level be S2 and S1 and intensities be I1 and I2
Difference in sound level(S) = S2 - S1 = 2dB
Using the relationship between difference in sound level and Intensity
S2 - S1 = 10log(I2 ÷ I1)
Note : Intensity is the square of the amplitude of sound
Therefore,
I1 = A1^2 and I2 = A2^2
Substituting the values into the equation:
S2 - S1 = 10log (I2 ÷ I1)
2dB = 10log (A2^2 ÷ A1^2)
2dB = 10log(A2 ÷ A1)^2
2 dB= 20log(A2 ÷ A1)
2÷20 = log (A2 ÷ A1)
0.1 = log (A2 ÷ A1)
(A2 ÷ A1) = 10^0.1
A2/A1 = 1.25
