Respuesta :
Weight G=m×g=0.55×9.8N
G=k×dx, where dx=2cm is the stretch.
dx=2cm=0.02m
m×g=k×dx
k=m×g/dx=0.55×9.8/0.02=269.5N/m
Answer: k=269.5N/m
The value of spring constant If a mass of 0.55kg attached to a vertical spring stretches the spring 2.0 cm from its original equilibrium is k=269.5N/m
What is spring constant?
The spring constant is defined as it is the ratio of force applied on the spring and the deflection of the spring.
The weight of the mass will be
F=m×g=0.55×9.8N
Spring force will be given as
F=k×dx, w
here dx=2cm is the stretch.
dx=2cm=0.02m
Since the weight of the mass will be equal to the force applied on the spring.
m×g=k×dx
k=m×g/dx=0.55×9.8/0.02=269.5N/m
k=269.5N/m
Hence value of spring constant If a mass of 0.55kg attached to a vertical spring stretches the spring 2.0 cm from its original equilibrium is k=269.5N/m
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