Question

Indicate a general rule for the nth term of the sequence a1 = 2 and r = √3.

an = (√3)(2)^n+1
an = (√3)(2)^n-1
an = (2)(√3)^n-1
an = (2)(√3)^n+1

Answer 1

It is given in the question that,

$a_{1} = 2, r = \sqrt 3$

Since we have the value of r given, so we have to use the formula to find the nth term of the geometric progression, which is

$a_{n} = a(r)^{n-1}$

Substituting the values of a and r, we will get

$a_{n} = 2( \sqrt 3)^{n-1}$

So the correct option is the third option .

Answer 2

Answer:

the correct answer is an = (2)(√3)^n-1