Answer:
The stresses in steel and the copper are, 128 ksi and 72.44 ksi, respectively.
Explanation:
In this case, we need to calculate the area of both portions separately.
Thus, we know that:
Inner Radius = Rin = (1/2 in)/2 = 0.25 in
Outer Radius = Rout = (5/8 in)/2 = 0.3125 in
FOR STEEL CORE:
Area of steel core = As = π(Rin)² = π(0.25 in)² = 0.0625 in²
Hence, the stress will be:
σs = Force / As
σs = 8000 lb/ 0.0625 in²
σs = 128 ksi
FOR COPPER:
Area of copper = Ac = π[(Rout)² - (Rin)²]
Ac = π[(0.3125 in)² - (0.25 in)²] = 0.11044 in²
Hence, the stress will be:
σc = Force / Ac
σc = 8000 lb/ 0.11044 in²
σc = 72.44 ksi
