Two birds start from the same nest and head off in opposite directions. The speed of the first bird is 15mph more than the speed of the second.After 6 hours the two birds are 402 miles apart. Find the speed of each bird?

Respuesta :

Answer: Speed  of first bird =41 mph

Speed of second bird = 26 mph

Step-by-step explanation:

Let x be the speed of the second bird, then the speed of first bird will be x+15.

After 6 hours ,

Distance covered by first bird= (x+15)(6)      [Distance = speed × time]

= 6x+90

Distance covered by second bird= (x)(6) = 6x

After 6 hours the two birds are 402 miles apart.

[tex]\Rightarrow\ 6x+90+6x=402\\\\\Rightarrrow\ 12x=402-90\\\\\Rightarrow\ 12x=312\\\\\Rightarrow\ x=\dfrac{312}{12}\\\\\Rightarrow\ x=\dfrac{312}{12}=26[/tex]

Speed of second bird = 26 mph, Speed  of first bird = 26+15 = 41 mph.

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