Question

1. The liquid in a tank weighs 38,300 pounds. The cylindrical tank has a diameter of 8 ft and is 10 ft high contains. What is the specific weight, mass density, and specific gravity of the liquid in the tank? Specific Weight = ______________________________ Mass Density = ________________________________ Specific Gravity = ______________________________

Answer 1

Answer:

Specific Weight = 76.19 lb/ft³  

mass density = 34.56

specific gravity = 1.22

Explanation:

given data

weighs = 38,300 pounds

diameter = 8 ft

high = 10 ft  

solution

we get here Specific Weight that is

Specific Weight = $\frac{weight}{volume}$   .................1

Specific Weight = $\frac{38300}{\pi r^2h }$  

Specific Weight = $\frac{38300}{\pi \times 4^2 \times 10}$

Specific Weight = 76.19 lb/ft³  

and

mass density = $\frac{m}{v}$    .............2

mass density = $\frac{38300}{\pi \times 4^2 \times 10 \times 2.2046}$

mass density = 34.56

and

specific gravity = $\frac{density (fluid)}{density(st.fluid)}$  ............3

specific gravity = $\frac{76.19}{62.43}$  

specific gravity = 1.22