Answer:
The theoretical yield is 1.73 grams
Explanation:
Step 1: Data given
Mass of methyl benzoate = 1.3 grams
Molar mass methyl benzoate = 136.15 g/mol
methyl benzoate = C8H8O2
Step 2: The balanced equation
C8H8O2 + HNO3 → C8H7O4N + H2O
Step 3: Calculate moles methyl benzoate
Moles methyl benzoate = mass / molar mass
Moles methyl benzoate = 1.3 grams / 136.15 grams
Moles methyl benzoate = 0.00955 moles
Step 4: Calculate moles C8H7O4N
For 1 mol methyl benzoate we need 1 mol HNO3 to produce 1 mol C8H7O4N and 1 mol H2O
For 0.00955 moles methyl benzoate we'll have 0.00955 moles C8H7O4N
Step 5: Calculate mass C8H7O4N
Mass C8H7O4N = moles * molar mass
Mass C8H7O4N = 0.00955 moles * 181.1455 g/mol
Mass C8H7O4N = 1.73 grams
The theoretical yield is 1.73 grams