Answer:
[tex]f(1) = - 11 \\ f(n)=f(n-1)+22[/tex]
Step-by-step explanation:
The function given is an explicit definition of a sequence.
[tex]f(n) = - 11 + 22(n -1 ).[/tex]
When n=1, we get:
[tex]f(1) = - 11 + 22(1-1) = - 11 + 22 \times 0[/tex]
This simplifies to:
The sequence is arithmetic with common difference d=22
The recursive definition is
[tex]f(n)=f(n-1)+d[/tex]
We substitute d=22 to obtain:
[tex]f(n)=f(n-1)+22[/tex]
