Answer:
a) 0.149
b) (0.135,0.163)
c) (0.134,0.164)
Step-by-step explanation:
We are given the following in the question:
a) Sample size, n = 2336
Number of people that have at least one tattoo, x = 349
Point Estimate:
[tex]\hat{p} = \dfrac{x}{n} = \dfrac{349}{2336} = 0.149[/tex]
b) 95% confidence interval:
[tex]\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]
[tex]z_{critical}\text{ at}~\alpha_{0.05} = 1.96[/tex]
Putting the values, we get:
[tex]0.149\pm 1.96(\sqrt{\dfrac{0.149(1-0.149)}{2336}}) = 0.149\pm 0.014\\\\=(0.135,0.163)[/tex]
c) 98% confidence interval
[tex]z_{critical}\text{ at}~\alpha_{0.02} = 2.05[/tex]
Putting the values, we get:
[tex]0.149\pm 2.05(\sqrt{\frac{0.149(1-0.149)}{2336}}) = 0.149\pm 0.015\\\\=(0.134,0.164)[/tex]
d) With increase in confidence level, the width of the confidence interval increases.