Answer with explanation:
→The quadratic function is
y = 3 x² + 12 x + 10
[tex]y=3(x^2+4 x+\frac{10}{3})\\\\y=3[(x+2)^2-4+\frac{10}{3}]\\\\y=3[(x+2)^2-\frac{2}{3}]\\\\y+2=3(x+2)^2[/tex]
→Vertex of the parabola=(-2,-2),in third Quadrant.
→Drawing the Parabola,which will open upwards ,that is along positive y axis.
→ Line, x= -2 , is the line of symmetry of Quadratic function.
As,the function is Quadratic, it has either two real root or two imaginary.
But, it has two real root, which are , x=-2.816,-1.184, because,
Discriminant >0.
D=12²-4×3×10
=144 -120
D=24
