Answer:
The height of the stacked boxes is 31 meters.
Step-by-step explanation:
Since, the Volume of a cube = (side)³
The volume of first box = 1331 cubic meters,
⇒ (side)³ = 1331
⇒
Similarly, the side of second box = 11 meters ( Because, both boxes have the same volume )
Now, the volume of third box = 729 cubic meters
⇒ ⇒ (side)³ = 729
⇒
Thus, the height of the stacked boxes = Side of first box + side of second box + side of third box
= 11 + 11 + 9
= 31 meters.
Answer:
31
Step-by-step explanation:
The volume of a cube is define as l x l x l= l(3) [l cubed]
So in the first case the volume =1331
From l x l x l= 1331; l= the cube root of (1331) = 11m;
So the total volume of the compactment is the sum of the 3 stacks= 1331 + 1331 + 729 = 2391 m3
Remember that volume is the same as base area X height
Let's denote this as V= B X h
Now h= V/ B
Remember that the first box placed at the base has a volume of 1331m3
That volume was a result of l x l x l= base area x height; the base area in this case= l x l ; since the surface facing the ground is a square.
With that in mind
The base area of the first cube= 11 X 11= 121
This area is the same as that of the whole stack;
Hence our formula H= V/ B can be used
h = 2391/121 =19.76m
Alternatively since this box is a solid box we take a look at the height of each box
Adding all 3 gives the height of the stack
The first two boxes are the same and the height is 11
Combining them we have 22m
The 3rd box height = the cube root of the volume of the third box = 9 [9x9x9=729]
Hence the total height of the compactment is
11+11+9=31m
31 is the most correct ; if it were a liquid volume that had to do with mixture ; the first answer would have been the most probable solution.
