Answer:
The y-intercept is the point (0,-8)
see the attached figure
Step-by-step explanation:
we have
[tex]f(x)=x^{2}-2x-8[/tex]
we know that
The y-intercept is the value of the function f(x) when the value of x is equal to zero
so
For x=0
[tex]f(x)=0^{2}-2(0)-8\\f(x)=-8[/tex]
therefore
The y-intercept is the point (0,-8)
see the attached figure to better understand the problem