Question

A 76.0 kg diver falls from rest into a swimming pool from a height of 3.90 m. It takes 1.82 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

Answer 1

Answer:

The  magnitude of the average force exerted on the diver during that time is 364.96 N.

Explanation:

Given that,

Mass of diver = 76.0 kg

Height = 3.90 m

Time = 1.82 s

We need to calculate the velocity

Using equation of motion

$v^2=u^2+2gh$

$v^2=2gh$

Put the value into the formula

$v=\sqrt{2\times9.8\times3,90}$

$v=8.74\ m/s$

We need to calculate the magnitude of the average force exerted on the diver during that time

Using formula of force

$F=\dfrac{mv}{t}$

Put the value into the formula

$F=\dfrac{76.0\times8.74}{1.82}$

$F=364.96\ N$

Hence, The  magnitude of the average force exerted on the diver during that time is 364.96 N.