Answer with Step-by-step explanation:
We are given that
RHS
[tex]\frac{1+Cos2x}{Sin2x}[/tex]
We have to verify the identity.
We know that
[tex]1+Cos2x=2Cos^2 x[/tex]
[tex]Sin2x=2SinxCos x[/tex]
Using the formula
[tex]\frac{2Cos^2x}{2SinxCosx}[/tex]
[tex]\frac{Cosx}{Sinx}[/tex]
[tex]Cot x[/tex]
By using the formula
[tex]Cotx=\frac{Cosx}{Sinx}[/tex]
LHS=RHS
Hence, verified