Question

what is the product? (4y − 3)(2y2 3y − 5)a. 8y3 3y 15b. 8y3 − 23y 15c. 8y3 − 6y2 − 17y 15d. 8y3 6y2 − 29y 15

Answer 1

$(4y-3)(2 y^{2} +3y-5) \\ =4y(2 y^{2} +3y-5)-3(2 y^{2} +3y-5) \\ =8 y^{3} +12 y^{2} -20y-6 y^{2} -9y+15 \\ =8 y^{3} +6 y^{2} -29y +15$

Answer 2

Answer:D!

Step-by-step explanation:

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