Question

How many moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess?

Answer 1

Answer: The number of moles of $NaCl$ produced will be, 3.61 moles.

Explanation : Given,

Mass of $Na$ = 83.0 g

Molar mass of $Na$ = 23 g/mol

First we have to calculate the moles of $Na$

$\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}$

$\text{Moles of }Na=\frac{83.0g}{23g/mol}=3.61mol$

Now we have to calculate the moles of $NaCl$

The balanced chemical equation is:

$2Na+Cl_2\rightarrow 2NaCl$

From the reaction, we conclude that

As, 2 mole of $Na$ react to give 2 mole of $NaCl$

So, 3.61 mole of $Na$ react to give 3.61 mole of $NaCl$

Therefore, the number of moles of $NaCl$ produced will be, 3.61 moles.

Answer 2

Answer:

2.57

Explanation: