How long is the arc intersected by a central angle of 5pi/3 radians in a circle with a radius of 2 ft? Round your answer to the nearest tenth. Use 3.14 for pi

A. 2.6 ft
B. 7.0 ft
C. 10.5 ft
D. 31.4 ft

Respuesta :

Length of an arc of a circle:
L = n / 2π ·2 ·r · π 
L = (5π/3 ·2 ·2 ·3.14 ) : 2π = 5/3 · 6.28 = 10.47 ≈ 10.5
Answer: C) 10.5 ft.

Answer:

C


Step-by-step explanation:

The arc length formula (in radians) is:

[tex]s=r\theta[/tex]

Where,

  • [tex]s[/tex] is the arc length
  • [tex]r[/tex] is the radius of the circle
  • [tex]\theta[/tex] is the angle intercepted by the arc [in radians]

It is given that radius, [tex]r=2[/tex]  and angle, [tex]\theta=\frac{5\pi}{3}[/tex]


Substituting these values in the arc length formula gives us:

[tex]s=(2)(\frac{5\pi}{3})\\s=\frac{10\pi}{3}[/tex]

Using [tex]\pi[/tex]  as [tex]3.14[/tex] and rounding to nearest tenth gives us:

[tex]s=\frac{(10)(\pi)}{3}\\s=10.5[/tex]  ft

Correct answer is C.

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