An aqueous solution 10 g of an optically pure substance diluted to 500ml with water and placed in a polarimeter tube 20 cm long. The measured rotation was -6.16. Calculate the specific rotation of this compound .

Respuesta :

Explanation:

Formula to calculate specific rotation is as follows.

        Specific rotation ([tex][\alpha][/tex]) = [tex]\frac{\alpha}{c} \times l[/tex]

where,    [tex]\alpha[/tex] = observed rotation

                   c = concentration in g/ml

                   l = path length in dm

It is given that,

             [tex]\alpha = -6.16^{o}[/tex]    

               c = [tex]\frac{10 g}{500 ml}[/tex] = 0.02 g/ml

              l = 20 cm = 2 dm   (as 1 dm = 10 cm)

Therefore, calculate the specific rotation as follows.

      Specific rotation ([tex][\alpha][/tex]) = [tex]\frac{\alpha}{c} \times l[/tex]

                        = [tex]\frac{-6.16^{o}}{0.02 g/ml} \times 2 dm[/tex]

                        = [tex]-616^{o}[/tex]

Thus, we can conclude that the specific rotation of this compound is [tex]-616^{o}[/tex].