Question

Calculate the pressure drop in a duct (measured by a differential oil manometer) if the differential height between the two fluid columns is 3.2 cm and the density of oil is 860 kg/m3 .

Answer 1

Answer:

The pressure drop is 269.7N/m^2

Explanation:

∆P = ∆h × rho × g

∆h = 3.2cm = 3.2/100 = 0.032m, rho = 860kg/m^3, g = 9.8m/s^2

∆P = 0.032×860×9.8 = 269.7N/m^2