Answer:
gauge pressure at the bottom = 59.35 kPa
Explanation:
given data
brine depth 1 = 2.2 m
oil depth 2 = 4.3 m
density of brine = 1,030 kg/m³
density of oil = 880 kg/m³
solution
we get here gauge pressure at the bottom of the tank that is
gauge pressure at the bottom = density of brine × g × height + density of oil × g × height ..............................1
put here value and we get
gauge pressure at the bottom = 1,030 × 9.81 ×2.2 + 880 ×9.81 ×4.3
gauge pressure at the bottom = 59350.5 N/m²
gauge pressure at the bottom = 59.35 kPa