Question

A 22-foot ladder is placed against a vertical wall of a building with the bottom of the ladder standing on level ground 17 feet from the base of the building how high up the wall does the ladder reach

Answer 1

Answer:

14 feet.

Step-by-step explanation:

Given: Length of ladder is 22 feet.

           Distance of bottom of ladder from base of building is 17 feet.

It form a right angle triangle with :

Agjacent= 17 feet

Hypotenous= 22 feet

Opposite = height of wall.

Lets assume the height of the wall does the ladder reach be "x".

Using pythagorean theorem to solve it.

We know, $h^{2} = a^{2} +b^{2}$

⇒ $22^{2} = 17^{2} +x^{2}$

⇒$484= 289+x^{2}$

Subtracting both side by 289

⇒$195= x^{2}$

taking square root on both side.

Remember; √a²= a

⇒$x= \sqrt{195}= 13.96 \approx 14 feet$

Hence, Wall is 14 feet high, where the ladder reach.