Answer:
a) 57
b) 76
c) 85
d) 133 - 19h
Step-by-step explanation:
Velocity is the derivative of position.
v(t) = s'(t) = [tex]171-38t[/tex]
For the intervals [a, b], the average velocity is given by [tex]\frac{v(a)+v(b)}{2}[/tex].
a) [1, 5]
v = [tex]\frac{v(1)+v(5)}{2} = \frac{133-19}{2}=57[/tex]
b) [1, 4]
v = [tex]\frac{v(1)+v(4)}{2} = \frac{133+19}{2}=76[/tex]
c) [1, 3]
v = [tex]\frac{v(1)+v(3)}{2} = \frac{133+57}{2}=85[/tex]
d) [1, 1+h]
v = [tex]\frac{v(1)+v(1+h)}{2} = \frac{133+171-38(1+h)}{2}=\frac{266-38h}{2}=133-19h[/tex]