Question

A ball is attached to the end of a string of length L, forming a pendulum. The period of the pendulum is 4.0 s. If the length of the string is doubled, now what is the period of oscillation?

Answer 1

Answer:

The period of oscillation when the lenght of the string is doubled is: T= 5.65 sec.

Explanation:

T1= 4s

L1=?

L2= 2L1=

T2= ?

g= 9.8 m/s²

T1= 2π √(L1/g)

clearing L1:

L1= 3.97m

L2= 7.94m

T2= 2π √(L2/g)

T2= 5.65 s