Respuesta :
Answer:
The time taken by the wave to travel along the combination of two wires is 458 ms.
Explanation:
Given that,
Length of steel wire= 27.0 m
Length of copper wire = 48.0 m
Tension = 145 N
Radius of both wires = 0.450 mm
Density of steel wire [tex]\rho_{s}= 7.86\times10^{3}\ kg/m^{3}[/tex]
Density of copper wire [tex]\rho_{c}=8.92\times10^{3}\ kg/m^3[/tex]
We need to calculate the linear density of steel wire
Using formula of linear density
[tex]\mu_{s}=\rho_{s}A[/tex]
[tex]\mu_{s}=\rho_{s}\times\pi r^2[/tex]
Put the value into the formula
[tex]\mu_{s}=7.86\times10^{3}\times\pi\times(0.450\times10^{-3})^2[/tex]
[tex]\mu_{s}=5.00\times10^{-3}\ kg/m[/tex]
We need to calculate the linear density of copper wire
Using formula of linear density
[tex]\mu_{c}=\rho_{s}A[/tex]
[tex]\mu_{c}=\rho_{s}\times\pi r^2[/tex]
Put the value into the formula
[tex]\mu_{c}=8.92\times10^{3}\times\pi\times(0.450\times10^{-3})^2[/tex]
[tex]\mu_{c}=5.67\times10^{-3}\ kg/m[/tex]
We need to calculate the velocity of the wave along the steel wire
Using formula of velocity
[tex]v_{s}=\sqrt{\dfrac{T}{\mu_{s}}}[/tex]
[tex]v_{s}=\sqrt{\dfrac{145}{5.00\times10^{-3}}}[/tex]
[tex]v_{s}=170.3\ m/s[/tex]
We need to calculate the velocity of the wave along the steel wire
Using formula of velocity
[tex]v_{c}=\sqrt{\dfrac{T}{\mu_{c}}}[/tex]
[tex]v_{c}=\sqrt{\dfrac{145}{5.67\times10^{-3}}}[/tex]
[tex]v_{c}=159.9\ m/s[/tex]
We need to calculate the time taken by the wave to travel along the combination of two wires
[tex]t=t_{s}+t_{c}[/tex]
[tex]t=\dfrac{l_{s}}{v_{s}}+\dfrac{l_{c}}{v_{c}}[/tex]
Put the value into the formula
[tex]t=\dfrac{27.0}{170.3}+\dfrac{48.0}{159.9}[/tex]
[tex]t=0.458\ sec[/tex]
[tex]t=458\ ms[/tex]
Hence, The time taken by the wave to travel along the combination of two wires is 458 ms.