Question

Mathematically combine the three given reactions so that they sum to give a balanced chemical equation describing the production of propane C3H8(g), from its elements, C(s.graphite) and H2lg). Show your intermediate steps. For example, if you must reverse reaction (c), enter the reverse in the appropriate answer box; if you multiply reaction

(a) by 2, enter the updated equation in the corresponding answer box. Make sure to enter the overall balanced equation at the bottom C3Hg(g)+502C2+H2O0)
(b) C(s)+02(g)> CO2(g)
(c) H2(«)+ 7o(Hod)

Answer 1

Answer :

The main balanced chemical reaction of the formation of propane will be:

$3C(s)+4H_2(g)\rightarrow C_3H_8(g)$

The given intermediate reactions are:

(a) $C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)$

(b) $C(s)+O_2(g)\rightarrow CO_2(g)$

(c) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$

For the formation of main balanced chemical reaction, we are reversing reaction (a), multiplying reaction (b) by 3, multiplying reaction (c) by 4 and then adding all the reactions, we get:

(a) $3CO_2(g)+4H_2O(l)\rightarrow C_3H_8(g)+5O_2(g)$

(b) $3C(s)+3O_2(g)\rightarrow 3CO_2(g)$

(c) $4H_2(g)+2O_2(g)\rightarrow 4H_2O(l)$

Thus, the main reaction will be:

$3C(s)+4H_2(g)\rightarrow C_3H_8(g)$