Question

i need a step by step to show that $4\sqrt[3]{3} *6\sqrt[3]{9}$ is 72 please!
if its write i will give brainliest

Answer 1

Answer:

We have the following expression:

$(4\sqrt[3]{3})(6\sqrt[3]{9})$

Which can be rewritten as:

$(6)(4)\sqrt[3]{3}\sqrt[3]{(3)(3)}$

Rearranging:

$24 \sqrt[3]{3}\sqrt[3]{3}\sqrt[3]{3}$

Since $\sqrt[3]{3}\sqrt[3]{3}\sqrt[3]{3}=(\sqrt[3]{3})^{3}=3$:

$(24)(3)=72$