Answer:
1.64 L
Explanation:
From the question we are given;
But, K = °C + 273
Therefore, final Temperature, T₁ = 25°C + 273
= 298 K
We are required to determine the new volume, V₂
That is;
[tex]V\alpha T[/tex]
Therefore;
[tex]V=kT[/tex]
At varying temperature and Volume
[tex]\frac{V_{1} }{T_1}=\frac{V_2}{T_2}[/tex]
Rearranging the formula;
[tex]V_2=\frac{V_1T_2}{T_1} \\\\=\frac{(1.5 L)(298K)}{273K} \\=1.64 L[/tex]
Thus, the new volume is 1.64 L