Respuesta :

Answer:

1.64 L

Explanation:

From the question we are given;

  • Initial volume, V₁ as 1.5 L
  • Initial temperature, T₁ as 273 K
  • Final temperature, T₂ as 25° C

But, K = °C + 273

Therefore, final Temperature, T₁ = 25°C + 273

                                                       = 298 K

We are required to determine the new volume, V₂

  • We are going to use Charles's law;
  • According to Charles's law the volume of a fixed mass and the absolute temperature are directly proportional at constant pressure.

That is;

[tex]V\alpha T[/tex]

Therefore;

[tex]V=kT[/tex]

At varying temperature and Volume

[tex]\frac{V_{1} }{T_1}=\frac{V_2}{T_2}[/tex]

Rearranging the formula;

[tex]V_2=\frac{V_1T_2}{T_1} \\\\=\frac{(1.5 L)(298K)}{273K} \\=1.64 L[/tex]

Thus, the new volume is 1.64 L

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