Answer:
9.6609 rad/s
10.143945 m/s
Explanation:
I = Moment of inertia = 3.75 kgm²
K = Kinetic energy = 175 J
r = Radius = 1.05 m
Kinetic energy is given by
[tex]K=\dfrac{1}{2}I\omega^2\\\Rightarrow \omega=\sqrt{\dfrac{2K}{I}}\\\Rightarrow \omega=\sqrt{\dfrac{2\times 175}{3.75}}\\\Rightarrow \omega=9.6609\ rad/s[/tex]
The angular velocity of the leg is 9.6609 rad/s
Velocity is given by
[tex]v=r\omega\\\Rightarrow v=1.05\times 9.6609\\\Rightarrow v=10.143945\ m/s[/tex]
The velocity of the tip of the punters shoe is 10.143945 m/s